Hi again,
I have a probelm with frameset. I would like to devide the screen to two screens.I used the frameset command to choose a pic (left screen) and I would like to change the picture on the right screen
(look at the code)
<%
dim conn,sql,rs
set conn=server.CreateObject("ADODB.connection")
conn.Open "dsn=futuremodels"
set rs=server.CreateObject("ADODB.recordset")
sql="select * from q_menu"
rs.Open sql,conn
Response.Write "<table border='0' width=80 align='left'>"
while not rs.EOF
Response.Write "<tr><td>"
Response.Write "<a href=" & "details.asp?id_detail=" & rs("id_detail") & " target='mainFrame'><IMG SRC='pictures/rightmenu/" & rs("mainfile") & "' width=80 height=122></td></tr>"
rs.MoveNext
wend
Response.Write "</table>"
rs.Close
set rs=nothing
conn.Close
set conn=nothing
%>
The problem is the left screen is waiting for a variable, so all I see is an error page until I click on one of the pic on the right screen
I do I solve the problem?
<%
dim id_detail
id_detail=Request.QueryString("id_detail")
dim conn,sql,rs
set conn=server.CreateObject("ADODB.connection")
conn.Open "dsn=futuremodels"
set rs=server.CreateObject("ADODB.recordset")
sql="select * from model_pic where id_detail=" & id_detail
rs.Open sql,conn
'while not rs.EOF
Response.Write "<IMG SRC='pictures/" & rs("filename") & "'>"
'rs.MoveNext
'wend
rs.Close
set rs=nothing
conn.Close
set conn=nothing
%>
