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helensnow
Posts: 232
Joined: 12/18/2003
Status: offline
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XMLhttp.Open `Post` - 4/21/2009 10:12:58
Hi
This is standard ASP coding to using xmlhttp.open to Post to a remote site. These examples are all over the web, and I noticed that they all have this error trap. On error resume next
Whern I removed this I get to see what the error is:-
msxml3.dll error '80004005'
Unspecified error
This error occurs explicity when the code line in red which sets the data format is executed
set xmlhttp = CreateObject("MSXML2.ServerXMLHTTP")
xmlhttp.setRequestHeader "Content-Type", "text/xml"
xmlhttp.open "POST", url, false
So clearly nothing past this point is going to work on a guaranteed basis, if there is an error
All I am trying to do is send data to a remote server, any ideas on what to do
Helen Snow
Deep in the white stuff
_____________________________
Love is all, and all that we are is love
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helensnow
Posts: 232
Joined: 12/18/2003
Status: offline
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RE: XMLhttp.Open `Post` - 4/25/2009 13:13:05
Hi,
Thanks for the info, I actually tried almost all the variations possible, and had to resort to ASP.NET which works perfectly.
Many thanks
Helen
_____________________________
Love is all, and all that we are is love
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