DateFormat Function
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hessfirm
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DateFormat Function
(9/28/2009 10:15:28)
Any idea how to get this function to return a 2 digit year versus 4?
Function DateFormat2(dt2)
DateFormat2 = left("00",2-len(month(dt2)))&month(dt2)&"/"&left("00",2-len(day(dt2)))&day(dt2)& "/"&year(dt2)
End Function
Thanks!
Spooky
->
RE: DateFormat Function
(9/29/2009 3:11:53)
right(year(dt2),2)
hessfirm
->
RE: DateFormat Function
(9/29/2009 10:39:04)
Can always count on this site for solid answers fast! Thanks Spooky!
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