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hessfirm
Posts: 155 Joined: 9/15/2004 Status: offline
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DateFormat Function - 9/28/2009 10:15:28
Any idea how to get this function to return a 2 digit year versus 4? Function DateFormat2(dt2) DateFormat2 = left("00",2-len(month(dt2)))&month(dt2)&"/"&left("00",2-len(day(dt2)))&day(dt2)& "/"&year(dt2) End Function Thanks!
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Steve Hess
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hessfirm
Posts: 155 Joined: 9/15/2004 Status: offline
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RE: DateFormat Function - 9/29/2009 10:39:04
Can always count on this site for solid answers fast! Thanks Spooky!
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Steve Hess
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